ORCHARD PARK, N.Y. — As if a primetime win over a division rival in his hometown wasn't enough, Bills running back James Cook is earning one more piece of recognition after shining in South Florida.
The NFL announced Wednesday that Cook is the Week 2 AFC Offensive Player of the Week.
The award comes on the heels of a dynamic performance from the third-year running back, totaling three total touchdowns and 95 total yards in the Bills 31-10 win over the Dolphins on Thursday night.
A native of Miami, Cook punctuated his return to South Florida with a 49-yard touchdown run in the third quarter, the longest touchdown run in the NFL this season. It was his second rushing touchdown of the night after recording a receiving touchdown as well in the first quarter.
Ahead of Bills practice Wednesday in Orchard Park, head coach Sean McDermott had praise for Cook's development since being drafted by Buffalo in 2022.
"His day-to-day approach is so steady," McDermott said. "Focused on what he needs to do to improve and really just again a delight to watch a young man come here from South Florida and really embrace Buffalo and the community and focus really hone in on his job and what he's trying to do so I know it means a lot to him to do his part and that's what you're seeing unfold here."
Cook is the second Bills player to earn conference weekly honors already this season. Defensive end Greg Rousseau was named AFC Defensive Player of the Week last week after his three-sack performance helped lift the Bills to a 34-28, season-opening win against the Cardinals.
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